(-0.6x^2)+(3.2x)-2.6=0

Solution for (-0.6x^2)+(3.2x)-2.6=0 equation:

(-0.6x^2)+(3.2x)-2.6=0

We add all the numbers together, and all the variables

(-0.6x^2)+(+3.2x)-2.6=0

We get rid of parentheses

-0.6x^2+3.2x-2.6=0

a = -0.6; b = 3.2; c = -2.6;
Δ = b2-4ac
Δ = 3.22-4·(-0.6)·(-2.6)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.2)-\sqrt{4}}{2*-0.6}=\frac{-3.2-\sqrt{4}}{-1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.2)+\sqrt{4}}{2*-0.6}=\frac{-3.2+\sqrt{4}}{-1.2}
$